(y^3+y+2)(y+1)=0

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Solution for (y^3+y+2)(y+1)=0 equation:


Simplifying
(y3 + y + 2)(y + 1) = 0

Reorder the terms:
(2 + y + y3)(y + 1) = 0

Reorder the terms:
(2 + y + y3)(1 + y) = 0

Multiply (2 + y + y3) * (1 + y)
(2(1 + y) + y(1 + y) + y3(1 + y)) = 0
((1 * 2 + y * 2) + y(1 + y) + y3(1 + y)) = 0
((2 + 2y) + y(1 + y) + y3(1 + y)) = 0
(2 + 2y + (1 * y + y * y) + y3(1 + y)) = 0
(2 + 2y + (1y + y2) + y3(1 + y)) = 0
(2 + 2y + 1y + y2 + (1 * y3 + y * y3)) = 0
(2 + 2y + 1y + y2 + (1y3 + y4)) = 0

Combine like terms: 2y + 1y = 3y
(2 + 3y + y2 + 1y3 + y4) = 0

Solving
2 + 3y + y2 + 1y3 + y4 = 0

Solving for variable 'y'.

The solution to this equation could not be determined.

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